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8a^2-29a-12=0
a = 8; b = -29; c = -12;
Δ = b2-4ac
Δ = -292-4·8·(-12)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-35}{2*8}=\frac{-6}{16} =-3/8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+35}{2*8}=\frac{64}{16} =4 $
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